Canada will play Romania in a Fed Cup

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(ISN) – Montreal,  – The International Tennis Federation (ITF) announced Tuesday that Canada will play Romania in a Fed Cup by BNP Paribas World Group playoff tie on April 18 and 19, 2015. The tie will be played in Canada. Choice of surface, venue, and team nominations will be decided at a later date.

“We are happy to have the chance to avenge our loss this weekend in front of our home fans in a little over two months,” said Sylvain Bruneau, captain of the Canadian Fed Cup team. “We know that Romania will be another tough test, but our team is gaining experience and I know they will be up to the challenge.”

Canada was relegated to a World Group playoff following its 4-0 defeat at the hands of the Czech Republic this past weekend. Without Eugenie Bouchard (Montreal, QC) and Aleksandra Wozniak (Blainville, QC), the squad consisted of Françoise Abanda (Montreal, QC), Gabriela Dabrowski (Ottawa, ON), Sharon Fichman (Toronto, ON), and Charlotte Robillard-Millette (Blainville, QC).

This will be just the second Fed Cup meeting between Canada and Romania. Their last meeting came in 1983 and the Romanians beat the Canadians 3-0.

Romania is trying to earn a place in the World Grou for the first time since 1992. This past weekend, the Romanian squad, led by Simona Halep, defeated Spain 3-2 thanks to decisive doubles win by Monica Niculescu and Irina-Camelia Begu over Anabel Medina Garrigues and Garbine Muguruza.

Canada is currently ranked no. 9 on the Fed Cup rankings while Romania is ranked no. 12.

WORLD GROUP PLAYOFF TIES

April 18-19, 2015

CANADA vs. Romania
ITALIE vs. United States
Netherlands vs. AUSTRALIA
POLAND vs. Switzerland

The host nations are listed first and the seeded countries are in capitals.

The four winning nations will qualify for the World Group in 2016 while the four losing nations will be relegated to World Group II for 2016.